We have already learnt that a rectangle is a special quadrilateral whose opposite sides are parallel.
 
But is every quadrilateral with parallel opposite sides a rectangle?
 
No.
If a quadrilateral has opposite sides parallel but its angles are not necessarily \(90^\circ\), it is called a parallelogram.
Parallelogram:
A parallelogram is a quadrilateral in which both pairs of opposite sides are parallel.
 
img62par.png
We know that a rectangle has opposite sides parallel. Therefore, it satisfies the definition of a parallelogram. Further, since all the angles of a rectangle are (\(90^\circ\)), a rectangle is a special type of parallelogram.
 
Thus, the Venn diagram is as follows.
 
Screenshot_1.png
 
Deduction 6: Opposite angles of a Parallelogram are equal.
Screenshot_3.png
Let \(∠A = x°\) in parallelogram \(ABCD\).
 
Statement  Reason
\(AB ∥ CD\) and \(AD\) is a transversal,
\(∠A + ∠D = 180°\)
\(∠D = 180° − x°\)
sum of the
internal angles on the same side of
a transversal is \(180°\).
\(AD ∥ BC\), \(AB\) is a transversal,
\(∠A + ∠B = 180°\)
\(∠B = 180° − x°\)
sum of the
internal angles on the same side of
a transversal is \(180°\).
This implies, \(∠D = ∠B = 180° − x°\) Same measure
\(AB ∥ DC\), \(BC\) is a transversal,
\(∠B + ∠C = 180°\),
\(∠C = 180° − ∠B = 180° − (180° − x°) = x°\)
Thus, \(∠A = ∠C = x°\)
sum of the
internal angles on the same side of
a transversal is \(180°\).
 
Therefore, \(∠A = ∠C\) and \( ∠B = ∠D\).
Deduction 7: Opposite Sides of a Parallelogram are equal.
Screenshot_4.png
 
Consider the triangles \(\triangle ABD\) and \(\triangle CDB\) in the parallelogram \(ABCD\).
 
Statement Reason
\(\angle DCB = \angle Bd\) Opposite angles of a parallelogram are equal.
\(\angle ADB =\angle CBD\) \(AD||BC\), \(BD\) is a transversal and since alternate angles are equal.
\(\triangle ABD \cong \triangle CDB\) \(AAS\) condition
\(AD = CB\) and \(AB=CD\) corresponding sides are equal
 
Thus, the opposite sides of a parallelogram are equal.
 
Deduction 8: Diagonals of a Parallelogram bisect each other.
Consider \(ABCD\) is a parallelogram.
 
The diagonals \(AC\) and \(BD\) intersect at \(O\).
 
Screenshot_6.png
 
Statement Reason
\(\triangle AOB\) \(\triangle DOC\), \(AB = DC\) Opposite sides of parallelogram
\(\angle OBA = \angle ODC\) Alternate angles, \(AB || DC\)
\(\angle OAB = \angle OCD\) Alternate angles
\(\triangle BOA \cong \triangle DOC\) \(ASA\) condition
\(OA = OC\) and \(OB=OD\) Congruent triangles
\(O\) bisects both diagonals \(OA = OC\) and \(OB=OD\)
 
Thus, the diagonals of the parallelogram bisect each other.
 
Important!
In a parallelogram if one angle is \(x^\circ\), then the angles are \(x^\circ\), \((180^\circ−x^\circ) \), \(x^\circ\), and \((180^\circ−x^\circ)\).
Rhombus
A rhombus is a special parallelogram.
 
Every rhombus is a parallelogram, but every parallelogram is not a rhombus
A rhombus is a quadrilateral in which all four sides are equal.
Now we are going to define a rhombus as a quadrilateral is a parallelogram with all the sides are in equal measures.
 
EX_12_1.png
 
Thus, if \(ABCD\) is a rhombus then \(AB=BC=CD=AD\), \(AB||CD\) and \(BC||AD\).
 
Deduction 9: In a Rhombus, Opposite Angles are Equal.
Consider a rhombus \(GAME\).
 
Screenshot_9.png
 
Statement Reason
In (∆GAE\), \(a = d\) \(GE = GA\)
In \(∆MAE\), \(b = c\) \(ME = MA\)
\(∆GAE ≅ ∆MAE\) and \(a = b\), \(c = d\) By \(SAS\)
 \(∠G = ∠M\) They are corresponding parts of congruent triangles)
 
 In a rhombus opposite angles are equal to each other.
 
A square is a special type of rectangle because each of its four angles is (\(90^\circ\)).
 
Since its opposite sides are parallel, it is also a parallelogram. In addition, all four sides of a square are equal in length, making it a rhombus as well. Hence, a square combines the properties of a rectangle, a parallelogram, and a rhombus.
 
Therefore, the relationship among these quadrilaterals can be represented using the following Venn diagram.
 
Screenshot_7.png
Deduction 10: Diagonals of a Rhombus are perpendicular bisector of each other.
 Screenshot_8.png
 
Consider the rhombus \(GAME\), diagonals meet at \(O\). In \(△GEO\) and \(△MEO\).
 
Statement Reason
\(GE = ME\) All sides of rhombus are equal
\(OE = OE\) common side
\(GO = MO\) Diagonals bisect each other in rhombus
\(△GEO ≅ △MEO\) By \(SSS\)
\(∠GOE = ∠MOE = \frac{180}{2} =90^\circ\) \(∠GOE + ∠MOE = 180°\) (linear pair)
diagonals are perpendicular bisector of each other  
 
Thus, the diagonals of the rhombus are perpendicular bisector of each other.
 
Property Parallelogram Rhombus
Definition A quadrilateral with both pairs of opposite sides parallel. A special parallelogram in which all four sides are equal.
Sides Opposite sides are equal. All four sides are equal.
Parallel Sides Opposite sides are parallel. Opposite sides are parallel.
Opposite Angles Opposite angles are equal. Opposite angles are equal.
Adjacent Angles Adjacent angles add up to \(180^\circ\). Adjacent angles add up to \(180^\circ\).
Diagonals Diagonals bisect each other. Diagonals bisect each other.
Length of Diagonals Diagonals are not always equal. Diagonals are not always equal.
Angle Between Diagonals Diagonals do not necessarily meet at \(90^\circ\). Diagonals always intersect at \(90^\circ\).
Diagonals and Angles Diagonals do not necessarily bisect the angles. Each diagonal bisects the opposite angles.