Expand \((y + 15z – 2)(6y + 9)\).
 
Answer:
 
\((y + 15z – 2)6y\) \(=\) iyi+izyiy
 
\((y + 15z – 2) 9\) \(=\) iy+izi
 
\((y + 15z – 2)(6y + 9)\) \(=\) iyiiy+iyz+izi