If \(a + b + c = 7\) and \(ab + bc + ca = 14\), then prove that \(a^3 + b^3 + c^3 - 3abc = 49\).
 
Proof
 
Using
 
ii=a2+b2+c2+2i
 
i=a2+b2+c2+i
 
a2+b2+c2=i - - - (i)
 
Now, using the identity
 
=iii (using eqns (i) and given)
 
=i