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Maths CBSE Live product
Class 9 (2026-27)
Exploring Algebraic Identities
Splitting the middle term
8.
TBQ - Prove the given statement
Question:
6
m.
If \(a + b + c = 7\) and \(ab + bc + ca = 14\), then prove that \(a^3 + b^3 + c^3 - 3abc = 49\).
Proof
:
Using
a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² - ab - bc - ca)
a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² + ab + bc + ca)
(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca
(a + b + c)² = a² + b² + c² - 2ab - 2bc - 2ca
i
i
=
a
2
+
b
2
+
c
2
+
2
i
i
=
a
2
+
b
2
+
c
2
+
i
a
2
+
b
2
+
c
2
=
i
- - - (i)
Now, using the identity
a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² + ab + bc + ca)
(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca
(a + b + c)² = a² + b² + c² - 2ab - 2bc - 2ca
a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² - ab - bc - ca)
=
i
i
−
i
(using eqns (i) and given)
=
i
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