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Answer variants:
ΔKON≅ΔMON
All the sides of a rhombus are equal
ΔKON≅ΔNMO
Diagonals of a parallelogram bisect each other
∠KON+∠NMO=180°
Opposite sides of a parallelogram are equal
All the sides of a parallelogram are equal
Using parallelogram property
∠KON=∠MON
ON=ON
∠KON+∠MON=180°
Using CPCT
∠KON=∠NMO
OK=MN
Show that the diagonals of a rhombus are perpendicular to each other.
 
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S. No.
Statement
Reason
1.
\(KLMN\) is a parallelogram.
Rhombus is also a parallelogram.
2.
OK=OM
3.
Common side
4.
KN=MN
5.
\(SSS\) Congruence rule
6.
CPCT
7.
Linear pair
8.
∠KON=90°
 
Hence, the diagonals of a rhombus are perpendicular to each other.