Construct a histogram to illustrate the following grouped frequency distribution:
 
Ages (in years) Number of teachers
\(20 - 24\) \(10\)
\(25 - 29\) \(28\)
\(30 - 34\) \(32\)
\(35 - 39\) \(48\)
\(40 - 44\) \(50\)
\(45 - 49\) \(35\)
\(50 - 54\) \(12\)
 
Solution: 
 
The given classes are series. Let us convert them into a series.
 
Consider the classes \(1\) and \(2\).
 
Class \(1\) ends with \(24\), and class \(2\) begins with \(25\).
 
The distance between classes \(1\) and \(2\) \(= 25 - 24 = 1\).
 
Lower boundary of class \(20 - 24\) \(= 20 - \frac{1}{2}(1)\)
 
\(= 20 - 0.5 = 19.5\)
 
Upper boundary of class \(20 - 24\) \(= 24 + \frac{1}{2}(1)\)
 
\(= 24 + 0.5 = 24.5\)
 
Therefore, the updated limit of class \(1\) is \(19.5 - 24.5\).
 
We get the continuous frequency distribution table by applying the concept to the remaining classes.
 
The histogram of the above data is:
 
YCIND_240320_6080_Statistics_7.png