In the below figure, \(PQ = PR\) and \(\angle Q = \angle R\). Prove that \(\triangle PQS \cong \triangle PRT\).
Proof :
In \(\triangle PQS\) and \(\triangle PRT\),
\(PQ = PR\) [Given]
\(\angle Q = \angle R\) [Given]
\(\angle QPS = \angle RPT\) []
Therefore, \(\triangle PQS \cong \triangle PRT\) [By congruence rule].