TBQ - Find the slope and intercept — task. Maths TNSB Mentoring, Class 10 Crash course.

Calculate the slope and \(y\) intercept of \(\sqrt{3}x + (1 - \sqrt{3})y = 15\).

Answer:

Rewrite the given equation in the form of

i = i i + i

Slope \(m =\)

\(y\) intercept \(=\)

Answer variants:

\frac{\sqrt{3} + 3}{2}

\frac{15 \sqrt{3} + 15}{- 2}

Did you find an error?

11. TBQ - Find the slope and intercept