Derive the equation of a line passing through \((10,-6)\) and perpendicular to the line joining the points \((6,7)\) and \((2,-3)\).
 
Answer:
 
The slope of the line joining the points \((6,7)\) and \((2,-3)\) is ii.
 
The slope of the line perpendicular to the line joining the points \((6,7)\) and \((2,-3)\) is iii.
 
The equation of the line is ii+iii=0.