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Maths TNSB Mentoring
Class 10 Crash course
Geometry
Annual Revision II
1.
PYQ - Find the appropriate answer
Question:
1
m.
In the given figure \(\angle BAC = 90^\circ\) and \(AD \perp BC\) then:
\(AB \cdot AC = BC^2\)
\(AB \cdot AC = AD^2\)
\(BD \cdot CD = BC^2\)
\(BD \cdot CD = AD^2\)
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