5. TBQ - Find the angle

\(PQ\) is a tangent drawn from a point \(P\) to a circle with centre \(O\) and \(QOR\) is a diameter of the circle such that \(\angle POR = 132^\circ\). Find \(\angle OPQ\).

 

Answer:

 

\(\angle OQP = 90^\circ\) [Since PQ is a tangent, it is parallel to the radius OQPQ is a tangent, it is perpendicular to the radius OQ.]

 

The angle \(OPQ\) \(=\) \(^\circ\)