TBQ - Answer the following — task. Maths TNSB Mentoring, Class 10 Crash course.

In above figure, \(DE || AC\) and \(DC || AQ\). Prove that

\frac{BE}{EC} = \frac{BC}{C Q}

Answer:

In \(\Delta BQA\), we have

DC ∥ i

By theorem:

\frac{BC}{i} = \frac{i}{DA}

- - - - - - (I)

In \(\Delta BCA\), we have

DE ∥ i

By theorem:

\frac{BE}{i} = \frac{i}{DA}

- - - - - - (II)

From (I) and (II), we get:

\frac{BE}{i} = \frac{i}{i}

Hence proved.

Did you find an error?

8. TBQ - Answer the following