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Subjects
Maths TNSB Mentoring
Class 10 Crash course
Numbers and Sequences
Annual Revision IV
8.
PYQ - Find the HCF of the given numbers
Question:
5
m.
Find
the HCF of \(825\), \(1050\) and \(885\).
Answer
:
1050
=
825
×
1
+
i
825
=
i
×
3
+
i
i
=
i
×
1
+
i
i
=
i
×
2
+
i
Thus, the HCF of
\(825\)
and
\(1050\)
is
.
885
=
i
×
11
+
i
i
=
i
×
1
+
i
i
=
i
×
4
+
i
Therefore,
the HCF of
\(825\), \(1050\), \(885\)
is
.
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