Find the HCF of \(825\), \(1050\) and \(885\).
 
Answer:
 
1050=825×1+i825=i×3+ii=i×1+ii=i×2+i
 
Thus, the HCF of \(825\) and \(1050\) is .
 
885=i×11+ii=i×1+ii=i×4+i
 
Therefore, the HCF of \(825\), \(1050\), \(885\) is .