The event \(A\), \(B\) and \(C\) are mutually inclusive. If \(P(A) = 0.32\), \(P(B) = 0.36\), \(P(C) = 0.31\), \(P(A \cap B) = 0.06\), \(P(B \cap C) = 0.11\), \(P(A \cap C) = 0.13\) and \(P(A \cap B \cap C) = 0.03\), then find the value of \(P(A \cup B \cup C)\).
Answer:
The value of \(P(A \cup B \cup C)\) \(=\) .