The event \(A\), \(B\) and \(C\) are non mutually exclusive. If \(P(A) = 0.33\), \(P(B) = 0.38\), \(P(C) = 0.29\), \(P(A \cap B) = 0.07\), \(P(B \cap C) = 0.1\), \(P(A \cap C) = 0.13\) and \(P(A \cup B \cup C) = 0.72\), then find the value of \(P(A \cap B \cap C)\).
Answer:
The value of \(P(A \cap B \cap C)\) \(=\) .