The perimeter of a rectangle is \(36\) metres and the length is \(2\) metres more than three times the width. Find the dimension of rectangle by using the method of graph.
Solution:
Let \(l\) denote the length and \(b\) denote the breadth of the rectangle.
From the given, let us frame the equation.
\(l = 18 - b\) ---- (\(1\))
Now, let us find the points for equation (\(1\)).
| \(b\) | \(2\) | \(4\) | \(5\) | \(8\) |
| \(l =\) |
The equation from the second statement is \(l = 3b + 2\) ---- (\(2\))
Now, let us find the points for equation (\(2\)).
| \(b\) | \(2\) | \(4\) | \(5\) | \(8\) |
| \(l = 3b + 2\) |
Length of rectangle \(=\) units.
Breadth of the rectangle \(=\) units.