Find the type of eye defect based on the near point given below and calculate the power:
The near point of a person with defect in his eye is \(4\ m\). What is the power of the lens required to correct this defect? Assume that the near point of the normal eye is \(25\ cm\).
The person is suffering from an eye defect called .
of suitable power can be used for the correction of this defect. It provide additional focusing power which is required for bringing the image back on the retina.
The normal human eye will be able to clearly see the object which is kept at the near point of the eye (that is \(25\ cm\)).
According to the lens formula,
Answer variants:
f
u
v
Substitute the values,
Focal length \(=\) \(m\)
The power (\(P\)) of a lens of focal length \(f\) is given by the relation,
Power of the lens \(=\) \(D\)
[Note: Enter the answer upto 2 decimal places.]