Find the type of eye defect based on the far point given below and calculate the power:
The far point of a defective eye person is \(40\ cm\) in front of the eye. What is the nature and power of the lens required correcting the problem?
The person is suffering from an eye defect called . In this defect, the image of the object is formed .
A of correct optical power can be used to correct this defect.
According to the lens formula,
Answer variants:
v
u
f
Substitute the values,
Focal length \(=\) \(m\)
The power (\(P\)) of a lens of focal length \(f\) is given by the relation,
Power of the lens \(=\) \(D\)
[Note: Enter the answer upto two decimal places.]