Prove the given trigonometric equation — task. Maths CBSE Live product, Class 10.

Answer variants:

\frac{\sin x (1 - \cos x)}{1 - \cos^{2} x}

\frac{\sin x (1 + \cos x)}{1 - \cos^{2} x}

\frac{\sin x}{1 + \cos x} \times \frac{1 - \cos x}{1 - \cos x}

\frac{\sin x (1 - \cos x)}{\sin^{2} x}

\frac{\sin x}{1 + \cos x} \times \frac{1 + \cos x}{1 + \cos x}

\frac{\sin x (1 - \cos x)}{(1 + \cos x) (1 - \cos x)}

\frac{\sin x}{1 + \cos x}

Show that

\frac{\sin x}{1 + \cos x}

\(=\)

\frac{1 - \cos x}{\sin x}

Proof:

LHS \(=\)

\frac{\sin x}{1 + \cos x}

\(=\)

\frac{1 - \cos x}{\sin x}

\(=\) RHS

Did you find an error?

5. Prove the given trigonometric equation