Show the given trigonometric equation — task. Maths CBSE Live product, Class 10 (2025-26).

Answer variants:

\frac{1 - \sin α}{\cos α}

\frac{1 + \sin α}{\cos α}

\frac{1 - \cos α}{\sin α}

\frac{\cos α (1 - \sin α)}{1 - \sin^{2} α}

\frac{\cos α (1 + \sin α)}{(1 + \sin α) (1 + \sin α)}

\frac{1}{\cos α} - \frac{\sin α}{\cos α}

\frac{\cos α (1 - \sin α)}{\cos^{2} α}

\frac{\cos α (1 - \sin α)}{(1 + \sin α) (1 - \sin α)}

\frac{\cos α (1 + \sin α)}{1 + \sin^{2} α}

Prove that

\frac{\cos α}{1 + \sin α}

\(=\)

\sec α - \tan α

Proof:

LHS \(=\)

\frac{\cos α}{1 + \sin α}

\(=\)

\sec α - \tan α

\(=\) RHS

Did you find an error?

6. Show the given trigonometric equation