Show the given trigonometric equation — task. Maths CBSE Live product, Class 10.

Show that

\frac{\cos θ}{1 + \sin θ}

\(=\)

\sec θ - \tan θ

Proof:

LHS \(=\)

\frac{\cos θ}{1 + \sin θ}

\(=\)

\sec θ - \tan θ

\(=\) RHS

Answer variants:

\frac{1}{\cos θ} - \frac{\sin θ}{\cos θ}

\frac{\cos θ (1 + \sin θ)}{(1 + \sin θ) (1 + \sin θ)}

\frac{\cos θ (1 - \sin θ)}{(1 + \sin θ) (1 - \sin θ)}

\frac{1 - \sin θ}{\cos θ}

\frac{\cos θ (1 - \sin θ)}{\cos^{2} θ}

\frac{\cos θ (1 + \sin θ)}{1 + \sin^{2} θ}

\frac{\cos θ (1 - \sin θ)}{1 - \sin^{2} θ}

Did you find an error?

4. Show the given trigonometric equation