Answer variants:
6
7.151
A boy observes a dog, at an angle of 40\(^{\circ}\) from the top of the building, 6 \(m\) above the ground. The dog runs towards the building through a distance, and its angle from the top of the building is \(45^{\circ}\). Find the distance the dog has moved. (Use \(tan \ 40^{\circ} = 0.839\))
Answer:
Let \(AB\) denote the height of the building.
\(BD = \)
\(BC = \)
The dog moved about a distance of \(m\).