In the adjoining figure, \(\Delta CAB\) is a right triangle, right angled at \(A\) and \(AD \perp BC\). Prove that \(\Delta ADB \sim \Delta CDA\). Further, if \(BC = 10 \ cm\) and \(CD = 1 \ cm\), calculate the length of \(AD\). 
 
YCIND_250613_7373_A_50.png
 
AD=icm