\(E\) and \(F\) are respectively the mid-points of equal sides \(AB\) and \(AC\) of \(∆ ABC\). Show that \(BF = CE\).
Proof:
In \(∆ ABF\) and \(∆ ACE\),
\(AB = \) (Given)
\(∠ A = ∠ A\) (Common)
\(AF = \) (Halves of equal sides)
So, by \(∆ ABF ≅ ∆ ACE\)
Therefore, \(BF = CE\) (By CPCT)
Hence, we proved.